16x^2+15x-31=5+15x

Solution for 16x^2+15x-31=5+15x equation:

16x^2+15x-31=5+15x

We move all terms to the left:

16x^2+15x-31-(5+15x)=0

We add all the numbers together, and all the variables

16x^2+15x-(15x+5)-31=0

We get rid of parentheses

16x^2+15x-15x-5-31=0

We add all the numbers together, and all the variables

16x^2-36=0

a = 16; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·16·(-36)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*16}=\frac{-48}{32}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*16}=\frac{48}{32}
=1+1/2
$